JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 8 April 2023, Shift 2, Physics Q48

Question 48 of 90 in this shift, Physics question 18 of 30, Section A.

An emf of 0.08 V is induced in a metal rod of length 10 cm held normal to a uniform magnetic field of 0.4 T, when moves with a velocity of:

(1) $20\ \mathrm{ms^{-1}}$
(2) $2\ \mathrm{ms^{-1}}$ Official answer
(3) $0.5\ \mathrm{ms^{-1}}$
(4) $3.2\ \mathrm{ms^{-1}}$

Official answer

Option 2

NTA final key.

Chapter: Electromagnetic Induction
Topic: Faraday's Law
Idea tested: Linear Motional EMF

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.