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Saturday, 31 October

JEE Main 2023 · ChemistryMultiple choiceMatch the listMediumRecall

JEE Main 8 April 2023, Shift 1, Chemistry Q76

Question 76 of 90 in this shift, Chemistry question 16 of 30, Section A.

Match List I with List II: [benzenediazonium chloride, C6H5N2Cl\mathrm{C_6H_5N_2Cl}] is reacted with reagents in List I to form products in List II. List I (Reagent) | List II (Product) A. [aniline, benzene ring with NH2\mathrm{NH_2}] | I. [fluorobenzene, benzene ring with F] B. HBF4\mathrm{HBF_4}, Δ\Delta | II. [benzonitrile, benzene ring with CN] C. Cu, HCl | III. [4-aminoazobenzene, C6H5−N=N−C6H4−NH2\mathrm{C_6H_5-N=N-C_6H_4-NH_2}] D. CuCN/KCN\mathrm{CuCN/KCN} | IV. [chlorobenzene, benzene ring with Cl] Choose the correct answer from the options given below:

The figure, in words

Stem shows benzenediazonium chloride (benzene ring with N2Cl). Table entries are structures: A aniline; I fluorobenzene; II benzonitrile; III Ph-N=N-C6H4-NH2 (para-aminoazobenzene); IV chlorobenzene.
  1. (1)A-IV, B-III, C-II, D-I
  2. (2)A-III, B-I, C-IV, D-IIOfficial answer
  3. (3)A-I, B-III, C-IV, D-II
  4. (4)A-III, B-I, C-II, D-IV

Official answer

Option 2

NTA final key.

Chapter
Amines
Topic
Diazonium Salts
Idea tested
Balz-Schiemann Reaction

Same idea in other shifts

Asked 2× in all
  1. 30 Jul 2022, Shift 2 · Q47[figure: six-membered ring with three alternating double bonds bearing N2+Cl−\mathrm{N_2^+Cl^-}, then '+ x' (lowercase x as printed) over a…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.