JEE Main 2022 (30 Jul, Shift 2) Chemistry Q47: Amines

Question

[figure: six-membered ring with three alternating double bonds bearing $\mathrm{N_2^+Cl^-}$, then '+ x' (lowercase x as printed) over a long arrow, to a six-membered ring with three alternating double bonds bearing $\mathrm{N_2^+BF_4^-}$; then an arrow with Y above and Cu, $\Delta$ below, to a six-membered ring with three alternating double bonds bearing $\mathrm{NO_2}$, labelled (Major Product)]
Consider the given chemical reaction, identify X and Y

Accepted Answer

Option 2: $\mathrm{X = HBF_4}$   $\mathrm{Y = NaNO_2}$

Answer

$\mathrm{X = BF_3}$   $\mathrm{Y = HNO_3}$

Answer

$\mathrm{X = HBF_4}$   $\mathrm{Y = NaNO_2}$

Answer

$\mathrm{X = HBF_4}$   $\mathrm{Y = HNO_3}$

Answer

$\mathrm{X = BF_3}$   $\mathrm{Y = NaNO_2}$

JEE Main 30 July 2022, Shift 2, Chemistry Q47

Same idea in other shifts