JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 6 April 2023, Shift 2, Physics Q47

Question 47 of 90 in this shift, Physics question 17 of 30, Section A.

A capacitor of capacitance 150.0

\mu

F is connected to an alternating source of emf given by

E=36\sin(120\pi t)

V. The maximum value of current in the circuit is approximately equal to :

(1) $\sqrt{2}A$
(2) $2\sqrt{2}A$
(3) $\frac{1}{\sqrt{2}}A$
(4) $2A$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Alternating Current
Topic: Phasor Diagrams
Idea tested: Phase Relations in RLC

Same idea in other shifts

Asked 8× in all

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13 Apr 2023, Shift 2 · Q44Given below are two statements: Statement I : An AC circuit undergoes electrical resonance if it contains either a capacitor or an…MediumTwo statements
28 Jul 2022, Shift 1 · Q44The equation of current in a purely inductive circuit is $5\sin(49\pi t-30^\circ)$ . If the inductance is 30 mH then the equation for the…MediumSingle correct
22 Jul 2021, Shift 2 · Q4In a circuit consisting of a capacitance and a generator with alternating emf $E_g = E_{g_0}\sin\omega t$ , $V_C$ and $I_C$ are the voltage…EasyDiagram basedHas a figure
17 Mar 2021, Shift 2 · Q7Match List - I with List - II List - I List - II (a) Phase difference between current and voltage in a purely resistive AC circuit (i)…EasyMatch the list
9 Jan 2020, Shift 2 · Q15In LC circuit the inductance $L = 40$ mH and capacitance $C = 100\ \mu$ F. If a voltage $V(t) = 10\sin(314\,t)$ is applied to the circuit,…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.