JEE Main 2023 (6 Apr, Shift 2) Physics Q46: The energy…

Question

The energy density associated with electric field $\vec{E}$ and magnetic field $\vec{B}$ of an electromagnetic wave in free space is given by ($\epsilon_0-$ permittivity of free space, $\mu_0=$ permeability of free space)

Accepted Answer

Option 4: $U_E=\frac{\epsilon_0 E^2}{2},\ U_B=\frac{B^2}{2\mu_0}$

Answer

$U_E=\frac{E^2}{2\epsilon_0},\ U_B=\frac{\mu_0 B^2}{2}$

Answer

$U_E=\frac{\epsilon_0 E^2}{2},\ U_B=\frac{\mu_0 B^2}{2}$

Answer

$U_E=\frac{E^2}{2\epsilon_0},\ U_B=\frac{B^2}{2\mu_0}$

Answer

$U_E=\frac{\epsilon_0 E^2}{2},\ U_B=\frac{B^2}{2\mu_0}$

JEE Main 6 April 2023, Shift 2, Physics Q46