JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 30 July 2022, Shift 2, Physics Q10

Question 10 of 90 in this shift, Physics question 10 of 30, Section A.

A charge q is uniformly distributed along the length L of a rod. It is then bent in the shape of a semicircle. The magnitude of electric field at the centre of semicircle will be :

(1) $\frac{q}{2 \in_0 L^2}$ Official answer
(2) $\frac{q}{2\pi \in_0 L^2}$
(3) $\frac{q}{2\pi \in_0 L}$
(4) $\frac{q}{4\pi^2 \in_0 L}$

Official answer

Option 1

NTA final key.

Chapter: Electric Charges and Fields
Topic: Electric Field
Idea tested: Charged Arc Field

Same idea in other shifts

Asked 4× in all

6 Apr 2026, Shift 1 · Q38A thin half ring of radius 35 cm is uniformly charged with a total charge of $Q$ coulomb. If the magnitude of the electric field at centre…MediumSingle correct
4 Apr 2025, Shift 2 · Q38A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB…MediumDiagram basedHas a figure
27 Aug 2021, Shift 2 · Q10Figure shows a rod AB, which is bent in a $120^\circ$ circular arc of radius R. A charge $(-Q)$ is uniformly distributed over rod AB. What…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.