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Saturday, 31 October

JEE Main 2025 · PhysicsMultiple choiceDiagram basedMediumApplication

JEE Main 4 April 2025, Shift 2, Physics Q38

Question 38 of 75 in this shift, Physics question 13 of 25, Section A.

A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB at 'O' is 'E' in magnitude. What would be the magnitude of electric field at 'O' due to arc ABC ?

The figure, in words

Uniformly charged (+) ring with centre O; mutually perpendicular diameters AC (vertical, A top, C bottom) and BD (horizontal, B right, D left).
  1. (1)2E2E
  2. (2)E/2E/2
  3. (3)2 E\sqrt{2}\,EOfficial answer
  4. (4)Zero

Official answer

Option 3

NTA final key.

Chapter
Electric Charges and Fields
Topic
Electric Field
Idea tested
Charged Arc Field

Same idea in other shifts

Asked 4× in all
  1. 6 Apr 2026, Shift 1 · Q38A thin half ring of radius 35 cm is uniformly charged with a total charge of QQ coulomb. If the magnitude of the electric field at centre…MediumSingle correct
  2. 30 Jul 2022, Shift 2 · Q10A charge q is uniformly distributed along the length L of a rod. It is then bent in the shape of a semicircle. The magnitude of electric…MediumSingle correct
  3. 27 Aug 2021, Shift 2 · Q10Figure shows a rod AB, which is bent in a 120∘120^\circ circular arc of radius R. A charge (−Q)(-Q) is uniformly distributed over rod AB. What…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.