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Saturday, 31 October

JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 26 July 2022, Shift 2, Physics Q54

Question 54 of 90 in this shift, Physics question 24 of 30, Section B.

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below : 12X+12X=24Y{}^{2}_{1}X + {}^{2}_{1}X = {}^{4}_{2}Y The binding energies per nucleon for 12X{}^{2}_{1}X and 24Y{}^{4}_{2}Y are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is ____________ MeV.

Official answer

26

NTA final key.

Chapter
Nuclei