JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 4 September 2020, Shift 2, Physics Q18

Question 18 of 75 in this shift, Physics question 18 of 25.

Find the Binding energy per neucleon for

^{120}_{50}\mathrm{Sn}

. Mass of proton

m_p = 1.00783

U, mass of neutron

m_n = 1.00867

U and mass of tin nucleus

m_{Sn} = 119.902199

U. (take 1U

=

931 MeV)

(1)8.0 MeV
(2)7.5 MeV
(3)8.5 MeVOfficial answer
(4)9.0 MeV

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Nuclei
Topic: Nuclear Binding Energy
Idea tested: Binding Energy per Nucleon

Same idea in other shifts

Asked 6× in all

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2 Apr 2025, Shift 2 · Q38Energy released when two deuterons ( $_1\mathrm{H}^2$ ) fuse to form a helium nucleus ( $_2\mathrm{He}^4$ ) is : (Given : Binding energy per…EasySingle correct
27 Jan 2024, Shift 1 · Q60In a nuclear fission process, a high mass nuclide (A $\approx$ 236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass…EasyNumerical value
8 Apr 2023, Shift 1 · Q55A nucleus with mass number $242$ and binding energy per nucleon as $7.6\ \mathrm{MeV}$ breaks into two fragment each with mass number…EasyNumerical value
26 Jul 2022, Shift 2 · Q54Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below : ${}^{2}_{1}X + {}^{2}_{1}X = {}^{4}_{2}Y$ …MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.