The area bounded by the curves $y=|x^2-1|$ and $y=1$ is

Option 4: $\frac{8}{3}\left(\sqrt{2}-1\right)$

$\frac{2}{3}\left(\sqrt{2}+1\right)$

$\frac{4}{3}\left(\sqrt{2}-1\right)$

$\frac{8}{3}\left(\sqrt{2}-1\right)$

JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 2, Maths Q20

Question 20 of 90 in this shift, Maths question 20 of 30, Section A.

The area bounded by the curves

y=|x^2-1|

and

y=1

(1) $\frac{2}{3}\left(\sqrt{2}+1\right)$
(2) $\frac{4}{3}\left(\sqrt{2}-1\right)$
(3) $2\left(\sqrt{2}-1\right)$
(4) $\frac{8}{3}\left(\sqrt{2}-1\right)$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Area with Modulus

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.