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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 26 July 2022, Shift 2, Maths Q19

Question 19 of 90 in this shift, Maths question 19 of 30, Section A.

The integral ∫(1−13)(cos⁡x−sin⁡x)(1+23sin⁡2x)dx\int\frac{\left(1-\frac{1}{\sqrt{3}}\right)(\cos x-\sin x)}{\left(1+\frac{2}{\sqrt{3}}\sin 2x\right)}dx is equal to
  1. (1)12log⁡e∣tan⁡(x2+π12)tan⁡(x2+π6)∣+C\frac{1}{2}\log_e\left|\frac{\tan\left(\frac{x}{2}+\frac{\pi}{12}\right)}{\tan\left(\frac{x}{2}+\frac{\pi}{6}\right)}\right|+COfficial answer
  2. (2)12log⁡e∣tan⁡(x2+π6)tan⁡(x2+π3)∣+C\frac{1}{2}\log_e\left|\frac{\tan\left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan\left(\frac{x}{2}+\frac{\pi}{3}\right)}\right|+C
  3. (3)log⁡e∣tan⁡(x2+π6)tan⁡(x2+π12)∣+C\log_e\left|\frac{\tan\left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan\left(\frac{x}{2}+\frac{\pi}{12}\right)}\right|+C
  4. (4)12log⁡e∣tan⁡(x2−π12)tan⁡(x2−π6)∣+C\frac{1}{2}\log_e\left|\frac{\tan\left(\frac{x}{2}-\frac{\pi}{12}\right)}{\tan\left(\frac{x}{2}-\frac{\pi}{6}\right)}\right|+C

Official answer

Option 1

NTA final key.

Chapter
Integrals

Same idea in other shifts

Asked 2× in all
  1. 4 Aug 2021, Shift 1 · Q86If ∫(tan⁡x+cot⁡x)dx=atan⁡−1(tan⁡x−1btan⁡x)+C\int\left(\sqrt{\tan x}+\sqrt{\cot x}\right)dx=a\tan^{-1}\left(\frac{\tan x-1}{\sqrt{b\tan x}}\right)+\mathrm{C}, then the value of…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.