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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 1, Maths Q7

Question 7 of 90 in this shift, Maths question 7 of 30, Section A.

If the function f(x)={log⁡e(1−x+x2)+log⁡e(1+x+x2)sec⁡x−cos⁡x,x∈(−π2,π2)−{0}k,x=0f(x) = \begin{cases} \dfrac{\log_e (1 - x + x^2) + \log_e (1 + x + x^2)}{\sec x - \cos x}, & x \in \left(\dfrac{-\pi}{2}, \dfrac{\pi}{2}\right) - \{0\} \\ \mathrm{k}, & x = 0 \end{cases} is continuous at x=0x = 0, then k is equal to :
  1. (1)11Official answer
  2. (2)−1-1
  3. (3)ee
  4. (4)00

Official answer

Option 1

NTA final key.