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Saturday, 31 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 18 March 2021, Shift 2, Chemistry Q55

Question 55 of 90 in this shift, Chemistry question 25 of 30, Section B.

The solubility of CdSO4\mathrm{CdSO_4} in water is 8.0×10−48.0 \times 10^{-4} mol L−1^{-1}. Its solubility in 0.01 M H2SO4\mathrm{H_2SO_4} solution is __________ ×10−6\times 10^{-6} mol L−1^{-1}. (Round off to the Nearest Integer). (Assume that solubility is much less than 0.01 M)

Official answer

64

NTA final key.