JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 24 February 2021, Shift 2, Chemistry Q55

Question 55 of 90 in this shift, Chemistry question 25 of 30, Section B.

The solubility product of

\mathrm{PbI_2}

8.0 \times 10^{-9}

. The solubility of lead iodide in 0.1 molar solution of lead nitrate is

x \times 10^{-6}

mol/L. The value of

x

is __________. (Rounded off to the nearest integer) [Given

\sqrt{2} = 1.41

]

Official answer

141

NTA final key.

Chapter: Equilibrium
Topic: Solubility Product
Idea tested: Common Ion Effect

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.