JEE Main 2021 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 25 July 2021, Shift 2, Maths Q90

Question 90 of 90 in this shift, Maths question 30 of 30, Section B.

Consider the function

f(x)=\begin{cases}\dfrac{P(x)}{\sin(x-2)}, & x\ne2\\ 7, & x=2\end{cases}

where

P(x)

is a polynomial such that

P''(x)

is always a constant and

P(3)=9

. If

f(x)

is continuous at

x=2

, then

P(5)

is equal to __________.

Official answer

NTA final key.

Chapter: Continuity and Differentiability
Topic: Continuity and Differentiability
Idea tested: Finding Unknown Constants via Continuity

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.