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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 31 August 2021, Shift 2, Physics Q6

Question 6 of 90 in this shift, Physics question 6 of 30, Section A.

If RER_E be the radius of Earth, then the ratio between the acceleration due to gravity at a depth 'r' below and a height 'r' above the earth surface is : (Given : r<REr < R_E)
  1. (1)1+rRE+r2RE2+r3RE31+\frac{r}{R_E}+\frac{r^2}{R_E^2}+\frac{r^3}{R_E^3}
  2. (2)1+rRE−r2RE2−r3RE31+\frac{r}{R_E}-\frac{r^2}{R_E^2}-\frac{r^3}{R_E^3}Official answer
  3. (3)1−rRE−r2RE2−r3RE31-\frac{r}{R_E}-\frac{r^2}{R_E^2}-\frac{r^3}{R_E^3}
  4. (4)1+rRE−r2RE2+r3RE31+\frac{r}{R_E}-\frac{r^2}{R_E^2}+\frac{r^3}{R_E^3}

Official answer

Option 2

NTA final key.

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.