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Saturday, 31 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 27 August 2021, Shift 1, Chemistry Q52

Question 52 of 90 in this shift, Chemistry question 22 of 30, Section B.

200 mL of 0.2 M HCl is mixed with 300 mL of 0.1 M NaOH. The molar heat of neutralization of this reaction is −57.1-57.1 kJ. The increase in temperature in °C of the system on mixing is x×10−2x \times 10^{-2}. The value of xx is __________. (Nearest integer) [Given : Specific heat of water = 4.18 J g−1 K−1\mathrm{g^{-1}\ K^{-1}} Density of water = 1.00 g cm−3\mathrm{cm^{-3}}] (Assume no volume change on mixing)

Official answer

82

NTA final key.

Chapter
Thermodynamics (Chemistry)
Topic
Enthalpy and Hess's Law
Idea tested
Constant Enthalpy of Neutralization

Same idea in other shifts

Asked 3× in all
  1. 5 Apr 2024, Shift 1 · Q72Given below are two statements : One is labelled as Assertion (A) and the other is labelled as Reason (R) Assertion (A) : Enthalpy of…EasyAssertion–reason
  2. 29 Jul 2022, Shift 1 · Q84When 600 mL of 0.2 M HNO3\mathrm{HNO_3} is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.