JEE Main 2021 · ChemistryNumerical answerNumerical valueHardCalculation

JEE Main 27 August 2021, Shift 1, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to

\frac{h^2}{x\,m\,a_0^2}

. The value of

10x

is __________. (

a_0

is radius of Bohr’s orbit) (Nearest integer) [ Given :

\pi = 3.14

]

Official answer

3155

NTA final key.

Chapter: Structure of Atom
Topic: Bohr's Atomic Theory
Idea tested: Angular Momentum Quantization

Same idea in other shifts

Asked 3× in all

15 Apr 2023, Shift 1 · Q62Given below are two statements: Statement I : According to Bohr's model of hydrogen atom, the angular momentum of an electron in a given…EasyTwo statements
9 Jan 2020, Shift 1 · Q26The de Broglie wavelength of an electron in the $4^{\mathrm{th}}$ Bohr orbit is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.