JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumMulti-step
JEE Main 4 August 2021, Shift 2, Chemistry Q44
Question 44 of 90 in this shift, Chemistry question 14 of 30, Section A.
The major products A and B in the following reaction sequence are
[reaction scheme: see figure_note]
(Ph = - )
The figure, in words
Reactant drawn: six-membered ring with a C=O (O drawn above). Arrow labelled '(i) C6H5MgBr dry ether, (ii) H3O+ (with a circled plus)' to A; second arrow labelled 'H2SO4, H2O' from A to B. Options drawn as labelled A = ..., B = ... skeletal rings with OH/Ph/O labels as described in the options.- (1)A = [six-membered ring with OH and Ph on one ring carbon], B = [six-membered ring with Ph on one ring carbon]
- (2)A = [six-membered ring with OH and Ph on one ring carbon], B = [six-membered ring with one C=C double bond, Ph on a carbon of the double bond]Official answer
- (3)A = [six-membered ring with =O on one ring carbon and Ph on the adjacent ring carbon], B = [six-membered ring with OH on one ring carbon, OH on the next ring carbon, and Ph on the ring carbon after that]
- (4)A = [six-membered ring with =O on one ring carbon and Ph on the adjacent ring carbon], B = [six-membered ring with a circle drawn inside, OH on one ring carbon and Ph on the adjacent ring carbon]
Official answer
Option 2
NTA final key.
- Chapter
- Alcohols, Phenols and Ethers
- Idea tested
- Grignard Reagent Addition