JEE Main 2020 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 3 September 2020, Shift 2, Chemistry Q46

Question 46 of 75 in this shift, Chemistry question 21 of 25.

6.023\times10^{22}

molecules are present in 10 g of a substance ‘

x

’. The molarity of a solution containing 5 g of substance ‘

x

’ in 2 L solution is __________

\times10^{-3}

Official answer

25.00

NTA final key (Sep 2020).

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Molarity Calculation

Same idea in other shifts

Asked 16× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.