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Saturday, 31 October

JEE Main 2026 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 6 April 2026, Shift 1, Maths Q24

Question 24 of 75 in this shift, Maths question 24 of 25, Section B.

For the functions f(θ)=αtan⁡2θ+βcot⁡2θf(\theta)=\alpha\tan^2\theta+\beta\cot^2\theta, and g(θ)=αsin⁡2θ+βcos⁡2θg(\theta)=\alpha\sin^2\theta+\beta\cos^2\theta, α>β>0\alpha>\beta>0, let min⁡0<θ<π2f(θ)=max⁡0<θ<πg(θ)\min_{0<\theta<\frac{\pi}{2}}f(\theta)=\max_{0<\theta<\pi}g(\theta). If the first term of a G.P. is (α2β)\left(\frac{\alpha}{2\beta}\right), its common ratio is (2βα)\left(\frac{2\beta}{\alpha}\right) and the sum of its first 10 terms is mn\frac{m}{n}, gcd⁡(m,n)=1\gcd(m,n)=1, then m+nm+n is equal to ________.

Official answer

1279

NTA final key.

Same idea in other shifts

Asked 10× in all
  1. 3 Apr 2025, Shift 1 · Q22All five letter words are made using all the letters A, B, C, D, E and arranged as in an English dictionary with serial numbers. Let the…HardNumerical value
  2. 29 Jan 2024, Shift 1 · Q7If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is…MediumSingle correct
  3. 28 Jul 2022, Shift 2 · Q86If 6312+10311+20310+4039+...+102403=2n⋅m\frac{6}{3^{12}}+\frac{10}{3^{11}}+\frac{20}{3^{10}}+\frac{40}{3^9}+...+\frac{10240}{3}=2^n\cdot m, where m is odd, then m⋅nm\cdot n…MediumNumerical value
  4. 25 Jun 2022, Shift 1 · Q4Let f:N→Rf:\mathbf{N}\to\mathbf{R} be a function such that f(x+y)=2f(x) f(y)f(x+y)=2f(x)\,f(y) for natural numbers xx and yy. If f(1)=2f(1)=2, then the value…MediumSingle correct
  5. 25 Jun 2022, Shift 1 · Q8If 12⋅310+122⋅39+…+1210⋅3=K210⋅310\frac{1}{2\cdot3^{10}}+\frac{1}{2^2\cdot3^9}+\ldots+\frac{1}{2^{10}\cdot3}=\frac{K}{2^{10}\cdot3^{10}}, then the remainder when K is…MediumSingle correct
  6. 25 Jun 2022, Shift 1 · Q30The greatest integer less than or equal to the sum of first 100 terms of the sequence…MediumNumerical value
  7. 9 Jan 2020, Shift 2 · Q57Let ana_n be the nthn^{\mathrm{th}} term of a G.P. of positive terms. If ∑n=1100a2n+1=200\sum_{n=1}^{100}a_{2n+1}=200 and ∑n=1100a2n=100\sum_{n=1}^{100}a_{2n}=100,…MediumSingle correct
  8. 5 Sep 2020, Shift 1 · Q57If 210+29⋅31+28⋅32+....+2⋅39+310=S−2112^{10}+2^{9}\cdot3^{1}+2^{8}\cdot3^{2}+....+2\cdot3^{9}+3^{10}=S-2^{11}, then S is equal to :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.