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JEE Main 5 September 2020, Shift 1, Maths Q57

Question 57 of 75 in this shift, Maths question 7 of 25.

2^{10}+2^{9}\cdot3^{1}+2^{8}\cdot3^{2}+....+2\cdot3^{9}+3^{10}=S-2^{11}

, then S is equal to :

(1) $3^{11}$ Official answer
(2) $2\cdot3^{11}$
(3) $3^{11}-2^{12}$
(4) $\frac{3^{11}}{2}+2^{10}$

Official answer

Option 1

NTA final key (Sep 2020).

Chapter: Sequences and Series
Topic: AP and GP
Idea tested: GP Sum of n terms

Same idea in other shifts

Asked 10× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.