JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 5 April 2026, Shift 1, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

Let

\tan A

\tan B

, where

A, B \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

, be the roots of the quadratic equation

x^2 - 2x - 5 = 0

. Then

20\sin^2\left(\frac{A+B}{2}\right)

is equal to:

(1) $10+\sqrt{10}$
(2) $10-2\sqrt{10}$
(3) $10-3\sqrt{10}$ Official answer
(4) $10-\sqrt{10}$

Official answer

Option 3

NTA final key.

Chapter: Trigonometric Functions
Topic: Trigonometric Identities
Idea tested: Compound Angle Formulas

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.