JEE Main 2020 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 8 January 2020, Shift 2, Maths Q75

Question 75 of 75 in this shift, Maths question 25 of 25, Section B.

\frac{\sqrt{2}\sin\alpha}{\sqrt{1 + \cos 2\alpha}} = \frac{1}{7}

and

\sqrt{\frac{1 - \cos 2\beta}{2}} = \frac{1}{\sqrt{10}}

\alpha, \beta \in \left(0, \frac{\pi}{2}\right)

, then

\tan(\alpha + 2\beta)

is equal to __________.

Official answer

1.00

NTA final key (Jan 2020).

Chapter: Trigonometric Functions
Topic: Trigonometric Identities
Idea tested: Compound Angle Formulas

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.