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JEE Main 2026 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 2, Maths Q13

Question 13 of 75 in this shift, Maths question 13 of 25, Section A.

Let

P = \{\theta \in [0, 4\pi]: \tan^2\theta \ne 1\}

and

S = \{a \in \mathbb{Z}: 2(\cos^8\theta - \sin^8\theta)\sec 2\theta = a^2, \theta \in P\}

. Then

n(S)

is:

(1) $0$ Official answer
(2) $1$
(3) $2$
(4) $3$

Official answer

Option 1

NTA final key.

Chapter: Trigonometric Functions
Topic: Trigonometric Identities
Idea tested: High Power Reduction Identities

Same idea in other shifts

Asked 2× in all

18 Mar 2021, Shift 2 · Q61If $15\sin^4\alpha + 10\cos^4\alpha = 6$ , for some $\alpha\in\mathbb{R}$ , then the value of $27\sec^6\alpha + 8\mathrm{cosec}^6\alpha$ is…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.