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Saturday, 31 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 1, Maths Q6

Question 6 of 75 in this shift, Maths question 6 of 25, Section A.

Let x1,x2,x3,x4x_1, x_2, x_3, x_4 be in a geometric progression. If 2,7,9,52, 7, 9, 5 are subtracted respectively from x1,x2,x3,x4x_1, x_2, x_3, x_4, then the resulting numbers are in an arithmetic progression. Then the value of 124(x1x2x3x4)\frac{1}{24}(x_1 x_2 x_3 x_4) is:
  1. (1)216216Official answer
  2. (2)7272
  3. (3)3636
  4. (4)1818

Official answer

Option 1

NTA final key.