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JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 7 April 2025, Shift 1, Physics Q35

Question 35 of 75 in this shift, Physics question 10 of 25, Section A.

An ac current is represented as

i = 5\sqrt{2} + 10\cos\left(650\pi t + \frac{\pi}{6}\right)

Amp The r.m.s value of the current is

(1) $5\sqrt{2}$ Amp
(2) $10$ AmpOfficial answer
(3) $50$ Amp
(4) $100$ Amp

Official answer

Option 2

NTA final key.

Chapter: Alternating Current
Topic: RMS and Peak Values
Idea tested: RMS of DC and AC Superposition

Same idea in other shifts

Asked 2× in all

27 Aug 2021, Shift 1 · Q28The alternating current is given by $i=\left\{\sqrt{42}\ \sin\left(\frac{2\pi}{\mathrm{T}}\mathrm{t}\right)+10\right\}$ A The r.m.s. value…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.