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Saturday, 31 October

JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumConceptual

JEE Main 7 April 2025, Shift 1, Physics Q26

Question 26 of 75 in this shift, Physics question 1 of 25, Section A.

If ϵ0\epsilon_0 denotes the permittivity of free space and ΦE\Phi_E is the flux of the electric field through the area bounded by the closed surface, then dimensions of (ϵ0dϕEdt)\left(\epsilon_0 \frac{d\phi_E}{dt}\right) are that of :
  1. (1)electric charge
  2. (2)electric potential
  3. (3)electric currentOfficial answer
  4. (4)electric field

Official answer

Option 3

NTA final key.