JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 30 January 2024, Shift 2, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

\mathrm{NO_2}

required for a reaction is produced by decomposition of

\mathrm{N_2O_5}

\mathrm{CCl_4}

as by equation

2\mathrm{N_2O_{5(g)}} \to 4\mathrm{NO_{2(g)}} + \mathrm{O_{2(g)}}

The initial concetration. of

\mathrm{N_2O_5}

is 3 mol L

^{-1}

and it is 2.75 mol L

^{-1}

after 30 minutes. The rate of formation of

\mathrm{NO_2}

is x

\times

^{-3}

mol L

^{-1}

min

^{-1}

, value of x is ________. (nearest integer)

Official answer

NTA final key.

Chapter: Chemical Kinetics
Topic: Rate Laws
Idea tested: Rate and Stoichiometry

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.