Learn

Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 30 January 2024, Shift 2, Chemistry Q80

Question 80 of 90 in this shift, Chemistry question 20 of 30, Section A.

A and B formed in the following reactions are: CrO2Cl2+4NaOH→A+2NaCl+2H2O\mathrm{CrO_2Cl_2} + 4\mathrm{NaOH} \to A + 2\mathrm{NaCl} + 2\mathrm{H_2O} A+2HCl+2H2O2→B+3H2OA + 2\mathrm{HCl} + 2\mathrm{H_2O_2} \to B + 3\mathrm{H_2O}
  1. (1)A=Na2Cr2O7, B=CrO3A = \mathrm{Na_2Cr_2O_7},\ B = \mathrm{CrO_3}
  2. (2)A=Na2Cr2O4, B=CrO4A = \mathrm{Na_2Cr_2O_4},\ B = \mathrm{CrO_4}
  3. (3)A=Na2Cr2O7, B=CrO5A = \mathrm{Na_2Cr_2O_7},\ B = \mathrm{CrO_5}
  4. (4)A=Na2CrO4, B=CrO5A = \mathrm{Na_2CrO_4},\ B = \mathrm{CrO_5}Official answer

Official answer

Option 4

NTA final key.