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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 30 January 2024, Shift 2, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4m4m, then the time period of small oscillations will be ________ ss. [take g=π2 ms−2g = \pi^2\ ms^{-2}]

Official answer

8

NTA final key.