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JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 30 January 2024, Shift 2, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

An alternating voltage

V(t) = 220\sin 100\pi t

volt is applied to a purely resistive load of

50\ \Omega

. The time taken for the current to rise from half of the peak value to the peak value is:

(1) $3.3\ ms$ Official answer
(2) $2.2\ ms$
(3) $7.2\ ms$
(4) $5\ ms$

Official answer

Option 1

NTA final key.

Chapter: Alternating Current
Topic: RMS and Peak Values
Idea tested: Time from Zero to Peak

Same idea in other shifts

Asked 2× in all

27 Jun 2022, Shift 1 · Q41The current flowing through an ac circuit is given by $I=5\sin(120\pi t)$ A How long will the current take to reach the peak value starting…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.