Learn

Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 30 January 2024, Shift 2, Maths Q2

Question 2 of 90 in this shift, Maths question 2 of 30, Section A.

If zz is a complex number, then the number of common roots of the equations z1985+z100+1=0z^{1985} + z^{100} + 1 = 0 and z3+2z2+2z+1=0z^3 + 2z^2 + 2z + 1 = 0, is equal to
  1. (1)00
  2. (2)11
  3. (3)22Official answer
  4. (4)33

Official answer

Option 3

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 26 Jun 2022, Shift 2 · Q23If z2+z+1=0z^2 + z + 1 = 0, z∈Cz \in \mathbb{C}, then ∣∑n=115(zn+(−1)n1zn)2∣\left|\sum_{n=1}^{15}\left(z^n + (-1)^n \frac{1}{z^n}\right)^2\right| is equal to ______.HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.