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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 30 January 2024, Shift 2, Maths Q16

Question 16 of 90 in this shift, Maths question 16 of 30, Section A.

If x2−y2+2hxy+2gx+2fy+c=0x^2 - y^2 + 2hxy + 2gx + 2fy + c = 0 is the locus of a point, which moves such that it is always equidistant from the lines x+2y+7=0x + 2y + 7 = 0 and 2x−y+8=02x - y + 8 = 0, then the value of g+c+h−fg + c + h - f equals
  1. (1)66
  2. (2)88
  3. (3)1414Official answer
  4. (4)2929

Official answer

Option 3

NTA final key.