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Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceOtherMediumRecall

JEE Main 30 January 2024, Shift 1, Chemistry Q75

Question 75 of 90 in this shift, Chemistry question 15 of 30, Section A.

In the given reactions, identify the reagent A and reagent B. [Scheme: toluene reacts via two routes to give benzaldehyde. Route 1: "A" + (CH3CO)2O\mathrm{(CH_3CO)_2O}, 273-283 K, gives [Intermediate], then H3O+\mathrm{H_3O^+}, Δ\Delta gives benzaldehyde (CHO). Route 2: "B" + CS2\mathrm{CS_2} gives [Intermediate], then H3O+\mathrm{H_3O^+} gives benzaldehyde (CHO).]

The figure, in words

Toluene (CH3 on benzene ring) with two reaction routes to benzaldehyde: route 1 reagent A + (CH3CO)2O at 273-283 K then H3O+ with heat; route 2 reagent B + CS2 then H3O+.
  1. (1)A-CrO3\mathrm{CrO_3} B-CrO3\mathrm{CrO_3}
  2. (2)A-CrO3\mathrm{CrO_3} B-CrO2Cl2\mathrm{CrO_2Cl_2}Official answer
  3. (3)A-CrO2Cl2\mathrm{CrO_2Cl_2} B-CrO3\mathrm{CrO_3}
  4. (4)A-CrO2Cl2\mathrm{CrO_2Cl_2} B-CrO2Cl2\mathrm{CrO_2Cl_2}

Official answer

Option 2

NTA final key.