JEE Main 2024 (30 Jan, Shift 1) Physics Q44: The electric…

Question

The electric field of an electromagnetic wave in free space is represented as $\vec{E} = E_0\cos(\omega t - kz)\,\hat{i}$. The corresponding magnetic induction vector will be :

Accepted Answer

Option 1: $\vec{B} = \frac{E_0}{C}\cos(\omega t - kz)\,\hat{j}$

Answer

$\vec{B} = \frac{E_0}{C}\cos(\omega t - kz)\,\hat{j}$

Answer

$\vec{B} = E_0 C\cos(\omega t - kz)\,\hat{j}$

Answer

$\vec{B} = \frac{E_0}{C}\cos(\omega t + kz)\,\hat{j}$

Answer

$\vec{B} = E_0 C\cos(\omega t + kz)\,\hat{j}$

JEE Main 30 January 2024, Shift 1, Physics Q44