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Saturday, 31 October

JEE Main 2024 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 30 January 2024, Shift 1, Maths Q27

Question 27 of 90 in this shift, Maths question 27 of 30, Section B.

Let the latus ractum of the hyperbola x29−y2b2=1\frac{x^2}{9}-\frac{y^2}{b^2}=1 subtend an angle of π3\frac{\pi}{3} at the centre of the hyperbola. If b2b^2 is equal to lm(1+n)\frac{l}{m}(1+\sqrt{n}), where ll and mm are co-prime numbers, then l2+m2+n2l^2+m^2+n^2 is equal to __________.

Official answer

182

NTA final key.

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.