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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 30 January 2024, Shift 1, Maths Q19

Question 19 of 90 in this shift, Maths question 19 of 30, Section A.

Let MM denote the median of the following frequency distribution Class: 0−40-4, 4−84-8, 8−128-12, 12−1612-16, 16−2016-20 Frequency: 33, 99, 1010, 88, 66 Then 20M20M is equal to :

The figure, in words

Frequency table: classes 0-4, 4-8, 8-12, 12-16, 16-20 with frequencies 3, 9, 10, 8, 6
  1. (1)5252
  2. (2)104104
  3. (3)208208Official answer
  4. (4)416416

Official answer

Option 3

NTA final key.

Chapter
Statistics
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.