JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 29 January 2024, Shift 1, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

For the reaction

\mathrm{N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}}

\mathrm{K_p}

= 0.492 atm at 300K.

\mathrm{K_c}

for the reaction at same temperature is ________

\times10^{-2}

. (Given : R = 0.082 L atm mol

^{-1}

^{-1}

)

Official answer

NTA final key.

Chapter: Equilibrium
Topic: Chemical Equilibrium
Idea tested: Kc and Kp Relationship

Same idea in other shifts

Asked 4× in all

6 Apr 2024, Shift 2 · Q63The ratio $\frac{K_P}{K_C}$ for the reaction : $\mathrm{CO_{(g)}+\frac{1}{2}O_{2(g)}\rightleftharpoons CO_{2(g)}}$ is :EasySingle correct
22 Jul 2021, Shift 2 · Q55Value of $\mathrm{K_p}$ for the equilibrium reaction $\mathrm{N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}}$ at 288 K is 47.9. The…EasyNumerical value
17 Mar 2021, Shift 2 · Q55Consider the reaction $\mathrm{N_2O_4(g) \rightleftharpoons 2NO_2(g)}$ . The temperature at which $\mathrm{K_C} = 20.4$ and…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.