JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 29 January 2024, Shift 1, Physics Q58

Question 58 of 90 in this shift, Physics question 28 of 30, Section B.

A square loop of side 10 cm and resistance

0.7\,\Omega

is placed vertically in east-west plane. A uniform magnetic field of

0.20\ T

is set up across the plane in north east direction. The magnetic field is decreased to zero in 1 s at a steady rate. Then, magnitude of induced emf is

\sqrt{x}\times10^{-3}\,V

. The value of

x

is ______.

Official answer

NTA final key.

Chapter: Electromagnetic Induction
Topic: Faraday's Law
Idea tested: Faraday's Law Magnitude

Same idea in other shifts

Asked 15× in all

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12 Apr 2023, Shift 1 · Q58A conducting circular loop is placed in a uniform magnetic field of 0.4 T with its plane perpendicular to the field. Somehow, the radius…MediumNumerical value
25 Jul 2022, Shift 2 · Q60Magnetic flux (in weber) in a closed circuit of resistance 20 $\Omega$ varies with time t(s) as $\phi$ = 8t $^{2}$ - 9t + 5. The magnitude…EasyNumerical value
26 Jul 2022, Shift 2 · Q58In a coil of resistance 8 $\Omega$ ,the magnetic flux due to an external magnetic field varies with time as…MediumNumerical value
27 Jul 2022, Shift 2 · Q54A conducting circular loop is placed in X - Y plane in presence of magnetic field $\vec{B}=\left(3t^3\hat{j}+3t^2\hat{k}\right)$ in SI…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.