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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 29 January 2024, Shift 1, Maths Q1

Question 1 of 90 in this shift, Maths question 1 of 30, Section A.

If f(x)={2+2x,−1≤x<01−x3,0≤x≤3f(x)=\begin{cases}2+2x, & -1\leq x<0\\ 1-\frac{x}{3}, & 0\leq x\leq 3\end{cases} ; g(x)={−x,−3≤x≤0x,0<x≤1g(x)=\begin{cases}-x, & -3\leq x\leq 0\\ x, & 0<x\leq 1\end{cases}, then range of (f∘g)(x)(f\circ g)(x) is
  1. (1)[0,3)[0,3)
  2. (2)[0,1][0,1]Official answer
  3. (3)[0,1)[0,1)
  4. (4)(0,1](0,1]

Official answer

Option 2

NTA final key.