JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyRecall

JEE Main 27 January 2024, Shift 1, Chemistry Q68

Question 68 of 90 in this shift, Chemistry question 8 of 30, Section A.

The electronic configuration for Neodymium is : [Atomic Number for Neodymium 60]

(1) $\mathrm{[Xe]\ 4f^{1}\ 5d^{1}\ 6s^2}$
(2) $\mathrm{[Xe]\ 4f^4\ 6s^2}$ Official answer
(3) $\mathrm{[Xe]\ 4f^6\ 6s^2}$
(4) $\mathrm{[Xe]\ 5f^7\ 7s^2}$

Official answer

Option 2

NTA final key.

Chapter: The d- and f-Block Elements
Topic: f-Block Elements
Idea tested: Lanthanide Electronic Configuration

Same idea in other shifts

Asked 8× in all

4 Apr 2026, Shift 2 · Q59Pairs of elements with the same number of electrons in their respective 4f orbital are [Atomic number: Eu-63, Gd-64, Dy-66, Ho-67, Tm-69,…MediumOther
6 Apr 2024, Shift 1 · Q69The number of element from the following that do not belong to lanthanoids is Eu, Cm, Er, Tb, Yb and LuEasySingle correct
27 Jun 2022, Shift 2 · Q69The 'f' orbitals are half and completely filled, respectively in lanthanide ions [Given : Atomic no. Eu, 63; Sm, 62; Tm, 69; Tb, 65; Yb,…MediumSingle correct
4 Aug 2021, Shift 1 · Q40Match List I with List II List I List II A. Gadolinium (At. No. 64) I. $5f^7, 6d^1, 7s^2$ B. Holmium (At. No. 67) II. $5f^4, 6d^1, 7s^2$ …MediumMatch the list
25 Jul 2021, Shift 2 · Q58Number of electrons present in 4f orbital of $\mathrm{Ho^{3+}}$ ion is ________. (Given Atomic No. of Ho = 67)EasyNumerical value
9 Jan 2020, Shift 1 · Q36The electronic configurations of bivalent europium and trivalent cerium are : (atomic number : Xe = 54, Ce = 58, Eu = 63)MediumSingle correct
5 Sep 2020, Shift 1 · Q37The correct electronic configuration and spin-only magnetic moment (BM) of $\mathrm{Gd^{3+}}$ ( $Z = 64$ ), respectively, are :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.