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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 1 February 2024, Shift 2, Chemistry Q85

Question 85 of 90 in this shift, Chemistry question 25 of 30, Section B.

Consider the following redox reaction : MnO4−+H++H2C2O4⇌Mn2++H2O+CO2\mathrm{MnO_4^- + H^+ + H_2C_2O_4 \rightleftharpoons Mn^{2+} + H_2O + CO_2} The standard reduction potentials are given as below (Ered∘\mathrm{E^\circ_{red}}) : EMnO4−/Mn2+∘=+1.51\mathrm{E^\circ_{MnO_4^-/Mn^{2+}}} = +1.51 V ECO2/H2C2O4∘=−0.49\mathrm{E^\circ_{CO_2/H_2C_2O_4}} = -0.49 V If the equilibrium constant of the above reaction is given as Keq=10x\mathrm{K_{eq}} = 10^x, then the value of xx = ________ (nearest integer)

Official answer

338

NTA final key.

Chapter
Electrochemistry
Topic
Nernst Equation
Idea tested
E°cell and Equilibrium

Same idea in other shifts

Asked 4× in all
  1. 3 Aug 2021, Shift 1 · Q56The logarithm of equilibrium constant (log⁡10\log_{10}K) for the reaction…MediumNumerical value
  2. 4 Aug 2021, Shift 2 · Q58The standard electrode potentials of the reactions are given below.…MediumNumerical value
  3. 8 Jan 2020, Shift 2 · Q48For an electrochemical cell Sn(s)∣Sn2+(aq, 1M)∣∣Pb2+(aq, 1M)∣Pb(s)\mathrm{Sn(s)|Sn^{2+}(aq,\ 1M)||Pb^{2+}(aq,\ 1M)|Pb(s)} the ratio…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.