JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 1 February 2024, Shift 2, Physics Q45

Question 45 of 90 in this shift, Physics question 15 of 30, Section A.

A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be :

(1) $30^\circ$
(2) $60^\circ$ Official answer
(3) $15^\circ$
(4) $45^\circ$

Official answer

Option 2

NTA final key.

Chapter: Wave Optics
Topic: Single Slit Diffraction
Idea tested: Angular Width of Central Max

Same idea in other shifts

Asked 3× in all

2 Apr 2026, Shift 1 · Q46In single slit diffraction pattern, the wavelength of light used is $628$ nm and slit width is $0.2$ mm, the angular width of central…EasyNumerical value
25 Feb 2021, Shift 2 · Q14Consider the diffraction pattern obtained from the sunlight incident on a pinhole of diameter 0.1 µm. If the diameter of the pinhole is…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.