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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 1 February 2024, Shift 1, Chemistry Q81

Question 81 of 90 in this shift, Chemistry question 21 of 30, Section B.

Consider the following reaction : 3PbCl2+2(NH4)3PO4→Pb3(PO4)2+6NH4Cl\mathrm{3PbCl_2 + 2(NH_4)_3PO_4 \rightarrow Pb_3(PO_4)_2 + 6NH_4Cl} If 72 mmol of PbCl2\mathrm{PbCl_2} is mixed with 50 mmol of (NH4)3PO4\mathrm{(NH_4)_3PO_4}, then the amount of Pb3(PO4)2\mathrm{Pb_3(PO_4)_2} formed is ________ mmol (nearest integer).

Official answer

24

NTA final key.