JEE Main 2024 (1 Feb, Shift 1) Physics Q32: A particle…

Question

A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle $	heta$ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection $	heta$ is then given by :

Accepted Answer

Option 2: $\sin^{-1}\left[\frac{2gT^2}{\pi^2 R}\right]^{\frac{1}{2}}$

Answer

$\cos^{-1}\left[\frac{2gT^2}{\pi^2 R}\right]^{\frac{1}{2}}$

Answer

$\sin^{-1}\left[\frac{2gT^2}{\pi^2 R}\right]^{\frac{1}{2}}$

Answer

$\sin^{-1}\left[\frac{\pi^2 R}{2gT^2}\right]^{\frac{1}{2}}$

Answer

$\cos^{-1}\left[\frac{\pi R}{2gT^2}\right]^{\frac{1}{2}}$

JEE Main 1 February 2024, Shift 1, Physics Q32

Same idea in other shifts