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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 1 February 2024, Shift 1, Maths Q19

Question 19 of 90 in this shift, Maths question 19 of 30, Section A.

Let a⃗=−5i^+j^−3k^\vec{a}=-5\hat{i}+\hat{j}-3\hat{k}, b⃗=i^+2j^−4k^\vec{b}=\hat{i}+2\hat{j}-4\hat{k} and c⃗=(((a⃗×b⃗)×i^)×i^)×i^\vec{c}=\left(\left(\left(\vec{a}\times\vec{b}\right)\times\hat{i}\right)\times\hat{i}\right)\times\hat{i}. Then c⃗⋅(−i^+j^+k^)\vec{c}\cdot\left(-\hat{i}+\hat{j}+\hat{k}\right) is equal to :
  1. (1)−10-10
  2. (2)−12-12Official answer
  3. (3)−13-13
  4. (4)−15-15

Official answer

Option 2

NTA final key.