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Saturday, 31 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 1 February 2024, Shift 1, Maths Q15

Question 15 of 90 in this shift, Maths question 15 of 30, Section A.

Let C:x2+y2=4C: x^2+y^2=4 and C′:x2+y2−4λx+9=0C': x^2+y^2-4\lambda x+9=0 be two circles. If the set of all values of λ\lambda so that the circles C and C' intersect at two distinct points, is R−[a,b]\mathbb{R}-[a,b], then the point (8a+12,16b−20)(8a+12, 16b-20) lies on the curve :
  1. (1)5x2−y=−115x^2-y=-11
  2. (2)6x2+y2=426x^2+y^2=42Official answer
  3. (3)x2−4y2=7x^2-4y^2=7
  4. (4)x2+2y2−5x+6y=3x^2+2y^2-5x+6y=3

Official answer

Option 2

NTA final key.