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Saturday, 31 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctHardApplication

JEE Main 9 April 2024, Shift 2, Chemistry Q75

Question 75 of 90 in this shift, Chemistry question 15 of 30, Section A.

[figure: C6H5−CH(CH3)−CH(OCH3)−Br\mathrm{C_6H_5-CH(CH_3)-CH(OCH_3)-Br} (benzylic carbon bearing CH3_3, next carbon bearing both OCH3_3 and Br)] →ΔKCN (alc)\xrightarrow[\Delta]{\mathrm{KCN\ (alc)}} Major Product 'P' In the above reaction product 'P' is

The figure, in words

Skeletal structure: phenyl ring attached to a carbon bearing a CH3 (drawn upward); the next carbon bears Br (drawn upper right) and OCH3 (drawn downward). Reagent KCN (alc), heat. Options are skeletal structures with CN, CH3, OCH3 and phenyl placed as described in each option.
  1. (1)[figure: C6H5−C(CH3)(CN)−CH2−OCH3\mathrm{C_6H_5-C(CH_3)(CN)-CH_2-OCH_3}]
  2. (2)[figure: C6H5−CH(CH3)−CH(CN)−OCH3\mathrm{C_6H_5-CH(CH_3)-CH(CN)-OCH_3}]Official answer
  3. (3)[figure: C6H5−CH(CN)−CH(CH3)−OCH3\mathrm{C_6H_5-CH(CN)-CH(CH_3)-OCH_3}]
  4. (4)[figure: C6H5−CH(OCH3)−CH(CH3)−CN\mathrm{C_6H_5-CH(OCH_3)-CH(CH_3)-CN}]

Official answer

Option 2

NTA final key.