JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 9 April 2024, Shift 2, Physics Q57

Question 57 of 90 in this shift, Physics question 27 of 30, Section B.

A particle of mass

0.50

kg executes simple harmonic motion under force

F=-50\ (Nm^{-1})x

. The time period of oscillation is

\frac{x}{35}

s. The value of

x

is __________. (Given

\pi=\frac{22}{7}

)

Official answer

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: SHM Definition and Force Law

Same idea in other shifts

Asked 5× in all

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10 Apr 2023, Shift 2 · Q51A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period…EasyNumerical value
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18 Mar 2021, Shift 2 · Q12The function of time representing a simple harmonic motion with a period of $\frac{\pi}{\omega}$ is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.